Physics Equation In Python

I want to make a program that can calculate physics equation where the user enters different parameters: I know its simple like: v=5 t=7 s=v*t print(s) its only calculating s = v*

Solution 1:

You could use key word arguments:

defsolve_equation(v=None, t=None, s=None):
    if v isnotNoneand t isnotNone:
        return v * t   # s caseelif s isnotNoneand t:  # t not None and not 0            return s / t   # v caseelse:
        raise ValueError   #"t should be defined or not zero"print(solve_equation(v=10, t=2))
print(solve_equation(s=2, t=7))

Output:

20
0.2857142857142857

Note that if you are using python 2, floats must be passed.

Solution 2:

Assuming you're talking about the zero acceleration "svt" equations (or even the constant acceleration "suvat" ones, should you have more complex requirements), it's a simple matter of detecting what's unknown, and then filling in the gaps.

The following code provides a function that will do this along with some test code so you can see it in action:

# Returns a 3-tuple containing [displacement(s), velocity(v), time(t)],#    based on the existence of at least two of those.# If all three are given, the displacement is adjusted so that the#    equation 's = vt' is correct.deffillInSvt(s = None, v = None, t = None):
    # Count the unknowns, two or more means no unique solution.

    noneCount = sum(x isNonefor x in [s, v, t])
    if noneCount > 1: return [None, None, None]

    # Solve for single unknown (or adjust s if none).if noneCount == 0or s isNone: return [v*t, v, t]
    if v isNone: return [s, s/t, t]
    return [s, v, s/v]

# Test code.print(fillInSvt(99,4,6))         # Show case that adjusts s.print(fillInSvt(None,4,6))       # Show cases that fill in unknown.print(fillInSvt(24,None,6))
print(fillInSvt(24,4,None))

print(fillInSvt(24,None,None))   # Show "not enough info" cases.print(fillInSvt(None,4,None))
print(fillInSvt(None,None,6))
print(fillInSvt(None,None,None))

The output shows that the tuple is filled in in all cases where there's a unique solution:

[24, 4, 6]
[24, 4, 6]
[24, 4.0, 6]
[24, 4, 6.0]
[None, None, None]
[None, None, None]
[None, None, None]
[None, None, None]

Solution 3:

I'm not sure if this is what you want, but you could define three separate functions, one for each variable. For example,

defs(v, t):
    return v*t

defv(s, t):
    return s/t

deft(s, v):
    return s/v

Solution 4:

def h2(v,d,t):
    title_ar = 'السرعة'
    title_en = 'speed'if v=='':
        print("v= ","%.2f"% (d/t),"m/s")
    elif d=='':
        print("d= ","%.2f"% (v*t),"m")
    elif t=='':
        print("t= ","%.2f"% (d/v),"s")
    else:
        print("please write all data.")

h2('', 2,6)
h2(70,'',8)
h2(25,3,'')