Reading All Numbers In File And Calculate Their Total In Python

I am trying to count all numbers in given file. It works unless there is a word between a numbers. e.g: 1 2 car 3 4 Here's my code: def main(): count=0 with open('numbers.txt', '

Solution 1:

You should move the try and except blocks inside your loop. Then when you hit a line with a non-number, you'll just skip it and go on the the next line.

Unrelated to that error, you can also simplify your code a bit by iterating over the file directly in a for loop, rather than calling readline repeatedly in a while loop:

withopen("numbers.txt", "r") as f:
    for line in f:          # simpler loopprint(line.strip())
        try:                # move this inside the loop
            count += int(line)
        except Exception as err: # you may only want to catch ValueErrors hereprint(err)

    print(count)

Solution 2:

you can use isdigit to check for number:

while line != '':
        print(line.strip())
        if line.strip().isdigit():
            count += int(line.strip())
        line = f.readline()

Here is Pythonic way to achieve this if you want to sum all digit:

f = open('file')
total_count = sum(int(x) for x in f if x.strip().isdigit())

if you want to count how many of them are digit:

f = open('file')
total_digit = len(x for x in f if x.strip().isdigit())

Solution 3:

You can use the isdigit method to check if the line contains only numbers:

def main():
    count=0
    with open("numbers.txt", "r") as f:
        count = sum(int(line) for line in f if line.strip().isdigit())
        print(count)

if __name__ == '__main__':
    main()

Solution 4:

You can try using regular expressions:

import re

total = 0withopen("numbers.txt", "r") as f:
    line = f.readline()
    while line != '':
        total += sum([int(x) for x in re.findall('(\\d+)', line)])
        line = f.readline()
print total